x^2+8x-725=0

Solution for x^2+8x-725=0 equation:

x^2+8x-725=0

a = 1; b = 8; c = -725;
Δ = b2-4ac
Δ = 82-4·1·(-725)
Δ = 2964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2964}=\sqrt{4*741}=\sqrt{4}*\sqrt{741}=2\sqrt{741}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{741}}{2*1}=\frac{-8-2\sqrt{741}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{741}}{2*1}=\frac{-8+2\sqrt{741}}{2}
$